题意：

求分钟和时钟之间的夹角

解法:俩个夹角互减

AC：10ms

#include
        
         #include
         
          #include
          
           #include
           
            #include
            
             using namespace std;int main(){		while (true)	{		int h, m;		scanf("%d:%d", &h, &m);		if(h == 0 && m == 0)			return 0;		double mm = m * 6;		//为什么是0.5 (m*6)*(1/12)		//1/12,分钟走360度,时钟走30度		double hh = h * 30 + m * 0.5;		double d = hh - mm;		if(d < 0)		{			d = d + 360;		}		if(d > 180)		{			d = 360 - d;		}		printf("%.3f\n", d);	}	return 0;}